Advertisements
Advertisements
प्रश्न
Construct `bar"X"` and R charts for the following data:
Sample Number | Observations | ||
1 | 32 | 36 | 42 |
2 | 28 | 32 | 40 |
3 | 39 | 52 | 28 |
4 | 50 | 42 | 31 |
5 | 42 | 45 | 34 |
6 | 50 | 29 | 21 |
7 | 44 | 52 | 35 |
8 | 22 | 35 | 44 |
(Given for n = 3, A2 = 1.023, D3 = 0 and D4 = 2.574)
उत्तर
We first find the sample mean and range for each of the 8 given samples.
Sample Number | Observations | `bar"X"` | R | ||
1 | 32 | 36 | 42 | 36.67 | 10 |
2 | 28 | 32 | 40 | 33.33 | 12 |
3 | 39 | 52 | 28 | 39.67 | 24 |
4 | 50 | 42 | 31 | 41 | 19 |
5 | 42 | 45 | 34 | 40.33 | 11 |
6 | 50 | 29 | 21 | 33.33 | 29 |
7 | 44 | 52 | 35 | 43.67 | 17 |
8 | 22 | 35 | 44 | 33.67 | 22 |
Total | 301.67 | 144 |
The control limits for `bar"X"` chart is
`\overset{==}{"X"} = (sumbar"X")/"Number of samples" = 301.67/8` = 37.71
`bar"R" = 144/8` = 18
UCL = `\overset{==}{"X"} + "A"_2 bar"R"`
= 37.71 + (0.58)(18)
= 37.71 + 10.44
= 48.15
CL = `\overset{==}{"X"}` = 37.71
LCL = `\overset{==}{"X"} - "A"_2 bar"R"`
= 37.71 – (0.58)(18)
= 37.71 – 10.44
= 27.27
The control limits for Range chart is
UCL = `"D"_4 bar"R"` = 2.115(18) = 38.07
CL = `bar"R"` = 18
LCL = `"D"_3 bar"R"` = 0(18) = 0
APPEARS IN
संबंधित प्रश्न
Define Statistical Quality Control
What do you mean by product control?
The following data show the values of sample mean `(bar"X")` and its range (R) for the samples of size five each. Calculate the values for control limits for mean, range chart and determine whether the process is in control.
Sample Number | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
Mean | 11.2 | 11.8 | 10.8 | 11.6 | 11.0 | 9.6 | 10.4 | 9.6 | 10.6 | 10.0 |
Range | 7 | 4 | 8 | 5 | 7 | 4 | 8 | 4 | 7 | 9 |
(conversion factors for n = 5, A2 = 0.58, D3 = 0 and D4 = 2.115)
A quality control inspector has taken ten ” samples of size four packets each from a potato chips company. The contents of the sample are given below, Calculate the control limits for mean and range chart.
Sample Number | Observations | |||
1 | 2 | 3 | 4 | |
1 | 12.5 | 12.3 | 12.6 | 12.7 |
2 | 12.8 | 12.4 | 12.4 | 12.8 |
3 | 12.1 | 12.6 | 12.5 | 12.4 |
4 | 12.2 | 12.6 | 12.5 | 12.3 |
5 | 12.4 | 12.5 | 12.5 | 12.5 |
6 | 12.3 | 12.4 | 12.6 | 12.6 |
7 | 12.6 | 12.7 | 12.5 | 12.8 |
8 | 12.4 | 12.3 | 12.6 | 12.5 |
9 | 12.6 | 12.5 | 12.3 | 12.6 |
10 | 12.1 | 12.7 | 12.5 | 12.8 |
(Given for n = 5, A2 = 0.58, D3 = 0 and D4 = 2.115)
In a certain bottling industry the quality control inspector recorded the weight of each of the 5 bottles selected at random during each hour of four hours in the morning.
Time | Weight in ml | ||||
8:00 AM | 43 | 41 | 42 | 43 | 41 |
9:00 AM | 40 | 39 | 40 | 39 | 44 |
10:00 AM | 42 | 42 | 43 | 38 | 40 |
11:00 AM | 39 | 43 | 40 | 39 | 42 |
Choose the correct alternative:
The quantities that can be numerically measured can be plotted on a
Choose the correct alternative:
Variations due to natural disorder is known as
Choose the correct alternative:
A typical control charts consists of
Choose the correct alternative:
`bar"X"` chart is a
The following data gives the average life(in hours) and range of 12 samples of 5lamps each. The data are
Sample No | 1 | 2 | 3 | 4 | 5 | 6 |
Sample Mean | 1080 | 1390 | 1460 | 1380 | 1230 | 1370 |
Sample Range | 410 | 670 | 180 | 320 | 690 | 450 |
Sample No | 7 | 8 | 9 | 10 | 11 | 12 |
Sample Mean | 1310 | 1630 | 1580 | 1510 | 1270 | 1200 |
Sample Range | 380 | 350 | 270 | 660 | 440 | 310 |
Construct control charts for mean and range. Comment on the control limits.