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प्रश्न
`"d"/"dx" [(cos x)^(log x)]` = ______.
पर्याय
`(cos x)^(log x) (1/x log cos x + tan x)`
`(cos x)^(log x) (1/x log cos x - tan x log x)`
`(cos x)^(log x) (1/x log cos x + log x)`
`(cos x)^(log x) (x log cos x - tan x log x)`
MCQ
रिकाम्या जागा भरा
उत्तर
`"d"/"dx" [(cos x)^(log x)] = underline((cos x)^(log x) (1/x log cos x - tan x log x))`.
Explanation:
Let y = `(cos x)^(log x)`
Taking logarithm on both sides, we get
log y = log x log (cos x)
Differentiating both sides w.r.t.x, we get
`1/"y" * "dy"/"dx" = log x * 1/(cos x) * (- sin x) + log (cos x) * 1/x`
`= "dy"/"dx" = (cos x)^(log x) (1/x log cos x - tan x log x)`
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