Advertisements
Advertisements
प्रश्न
Define Hydrolysis of salt.
उत्तर
Hydrolysis of salt is defined as the reaction in which cations or anions or both ions of a salt react with ions of water to produce acidity or alkalinity (or sometimes even neutrality).
APPEARS IN
संबंधित प्रश्न
Answer the following in one sentence :
Why is KCl solution neutral to litmus?
Answer the following :
What is meant by hydrolysis?
Give any one example of salt derived from weak acid and weak base.
NH4CN is a salt of ____________.
Find the CORRECT match.
Which of the following salts do not undergo hydrolysis?
i. CH3COONa
ii. CuSO4
iii. NaCl
iv. NH4NO3
v. K2SO4
Identify Z in the sequence.
\[\ce{CH3COONH4 ->[\Delta] X ->[P2O5][\Delta] Y ->[H2O/H^+] Z}\]
Why is it necessary to add H2SO4 while preparing the solution of CuSO4?
Answer the following in one sentence :
Why is it necessary to add H2 SO4 while preparing the solution of CuSO4?
Write hydrolysis reaction of iodine trichloride.
Define hydrolysis.
Which one of the following salts does not hydrolyse in water?
A salt of strong acid and strong base does not undergo hydrolysis. Explain.
Give an example of a salt of weak acid and weak base.
Why is it necessary to add H2SO4 while preparing the solution of CuSO4?
Why is it necessary to add \[\ce{H2SO4}\] while preparing the solution of \[\ce{CuSO4}\]?
Answer the following in one sentence:
Why is it necessary to add \[\ce{H2SO4}\] while preparing the solution of \[\ce{CuSO4}\]?
Answer the following in one sentence:
Why is it necessary to add \[\ce{H2 SO4}\] while preparing the solution of \[\ce{CuSO4}\]?
Why is it necessary to add \[\ce{H2SO4}\] while preparing the solution of \[\ce{CuSO4}\]?
Answer the following in one sentence:
Why is it necessary to add H2SO4 while preparing the solution of CuSO4?
Answer the following in one sentence:
Why is it necessary to add \[\ce{H2SO4}\] while preparing the solution of \[\ce{CuSO4}\]?
Answer the following in one sentence:
Why is it necessary to add \[\ce{H2SO4}\] while preparing the solution of \[\ce{CuSO4}\]?
