मराठी

Degree of the given differential equation (("d"^3"y")/"dx"^2)^2 = (1 + "dy"/"dx")^(1/3) is -

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प्रश्न

Degree of the given differential equation

`(("d"^3"y")/"dx"^2)^2 = (1 + "dy"/"dx")^(1/3)` is

पर्याय

  • 2

  • 3

  • `1/2`

  • 6

MCQ

उत्तर

6

Explanation:

`(("d"^3"y")/"dx"^2)^2 = (1 + "dy"/"dx")^(1/3)`

`=> (("d"^2"y")/"dx"^3)^6 = 1 + "dy"/"dx"`

Here, the highest order derivative is `("d"^3"y")/"dx"^3` with power 6.

∴ degree = 6

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