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Describe the New Cartesian Sigh Convention Used in Optics. Draw a Labelled Diagram to Illustrate this Sign Convention. - Science

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प्रश्न

Describe the New Cartesian Sigh Convention used in optics. Draw a labelled diagram to illustrate this sign convention.

उत्तर

According to the new cartesian sign convention :

  1. All distances are measured from the pole of the mirror as origin.
  2. Distances measured in the same direction as that of incident light are taken as positive.
  3. Distances measured against the direction of incident light are taken as negative.
  4. Distances measured upward and perpendicular to the principal axis are taken as positive.
  5. Distances measured downward and perpendicular to the principal axis are taken as negative.  

 

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पाठ 4: Reflection of Light - Exercise 4 [पृष्ठ १९२]

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लखमीर सिंह Physics (Science) [English] Class 10
पाठ 4 Reflection of Light
Exercise 4 | Q 7 | पृष्ठ १९२

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संबंधित प्रश्‍न

The height of the image formed by an object of height 10 cm placed in front of a plane mirror is __________.

(a) 5 cm
(b) 10 cm
(c) 15 cm
(d) 20 cm


Where should an object be placed in front of the concave mirror so as to obtain its virtual, erect and magnified image?


What sign (+ve or −ve) has been given to the following on the basis of Cartesian Sigh Convention?  

Height of a real image. 


According to New Cartesian Sign Convention:

(a) focal length of concave mirror is positive and that of convex mirror is negative
(b) focal length of both concave and convex mirrors is positive
(c) focal length of both concave and convex mirrors is negative
(d) focal length of concave mirror is negative and that of convex mirror is positive


What is the nature of image formed by a concave mirror if the magnification produced by the mirror  

 +4 


Fill in the following blank with suitable word: 

If the magnification has a minus sign, than the image is ......... and .......


An object is placed at a distance of 100 cm from a converging lens of focal length 40 cm.
(i) What is the nature of image?
(ii) What is the position of image?


At what distance should an object be placed from a convex lens of focal length 18 cm to obtain an image at 24 cm from it on the other side? What will be the magnification produced in this case?


An object is 0.09 m from a magnifying lens and the image is formed 36 cm from the lens. The magnification produced is:
(a) 0.4
(b) 1.4
(c) 4.0
(d) 4.5 


An image formed on a screen is three times the size of the object. The object and screen are 80 cm apart when the image is sharply focussed. 

 Calculate focal length of the lens.


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