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प्रश्न
Design n class to overload a function SumSeriesO as follows:
(i)
void SumSeries(int n, double x) – with one integer argument and one double argument to find and display the sum of the series given below:
`"s" = "x"/1 - "x"/2 + "x"/3 - "x"/4 + "x"/5`...... ...... ...... to n terms
(ii)
void SumSeries() – To find and display the sum of the following series:
s = 1 + (1 x 2) + (1 x 2 x 3) + ….. + (1 x 2 x 3 x 4 x 20)
उत्तर
class Overload
{
void SumSeries (int n, double x)
{
double sum = 0;
for (int k = 1; k<=n; k++)
{
t = x / k;
if (k% 2 = = 1)
sum = sum + t:
else
sum = sum - t:
}
System.out.println ("sum is" + sum);
}
void SumSeries ()
{
long f, s = 0;
for (int a = 1; a<=20; a++)
{
f = 1;
for (int b = 1; b <=a; b++)
}
f = f ∗ b;
}
S = S + f;
}
System.out.println ("Sum" + S);
}
}
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संबंधित प्रश्न
Define a class to overload the function print as follows:
| void print() | to print the following format | |||
| 1 | 1 | 1 | 1 | |
| 2 | 2 | 2 | 2 | |
| 3 | 3 | 3 | 3 | |
| 4 | 4 | 4 | 4 | |
| 5 | 5 | 5 | 5 | |
| void print(int n) | To check whether the number is a lead number. A lead number is one whose sum of even digits is equal to the sum of odd digits. |
|
e.g. 3669 odd digits sum = 3 + 9 = 12 |
Define a class to overload the method display() as follows:
void display(): To print the following format using nested loop.
1 2 1 2 1
1 2 1 2 1
1 2 1 2 1
void display (int n, int m): To print the quotient of the division of m and n if m is greater than n otherwise print the sum of twice n and thrice m. double display (double a, double b, double c) - to print the value of z where
z = p × q
`p=(a+b)/c` q = a + b + c
