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प्रश्न
Determine whether the following function is odd or even?
f(x) = x + x2
बेरीज
उत्तर
f(x) = x + x2
f(-x) = (-x) + (-x)2 = -x + x2
Since f(-x) ≠ f(x), f(-x) ≠ -f(x).
∴ f(x) is neither odd nor even function.
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