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प्रश्न
Direction cosines of the line `(x + 2)/2 = (2y - 5)/3, z = -1` are ______.
पर्याय
`4/5, 3/5, 0`
`3/5, 4/5, 1/5`
`-3/5, 4/5, 0`
`4/5, -2/5, 1/5`
MCQ
रिकाम्या जागा भरा
उत्तर
Direction cosines of the line `(x + 2)/2 = (2y - 5)/3, z = -1` are `underlinebb(4/5, 3/5, 0)`.
Explanation:
Equation of given line is
`(x + 2)/2 = (2y - 5)/3, z + 1` = 0
or `(x + 2)/2 = (y - 5/2)/(3/2), z + 1` = 0
So, DR of given line are `< 2, 3/2, 0 >`
As, `sqrt(2^2 + (3/2)^2 + 0)`
= `sqrt(4 + 9/4)`
= `sqrt(25/4)`
= `5/2`
∴ DC of given line are `< 2/(5/2), (3/2)/(5/2), 0 >` or `< 4/5, 3/5, 0 >`
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Scalar Product of Vectors (Dot)
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