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प्रश्न
Divide:
15x3y2 + 25x2y3 − 36x4y4 by 5x2y2
बेरीज
उत्तर
15x3y2 + 25x2y3 − 36x4y4 by 5x2y2
= `(15"x"^3"y"^2+25"x"^2"y"^3-36"x"^4"y"^4)/(5"x"^2"y"^2)`
= `(15"x"^3"y"^2)/(5"x"^2"y"^2)+(25"x"^2"y"^3)/(5"x"^2"y"^2)-(36"x"^4"y"^4)/(5"x"^2"y"^2)`
`=3"x"^(3-2)."y"^(2-2)+5"x"^(2-2)."y"^(3-2)-36/5"x"^(4-2)."y"^ (4-2)`
= `3"x"^1"y"^0+5"x"^0"y"^1-36/5"x"^2"y"^2`
= `3"x"+5"y"-36/5"x"^2"y"^2` ...........(∵ x0 or y0 = 1)
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