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प्रश्न
Divide:
20x2 by 5x
बेरीज
उत्तर
`20"x"^2÷5"x"=(4xx5xx"x"^(2-1))/5=4"x"`
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Concept for Unknowns Through Examples with Simple Contexts (Single Operations)
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संबंधित प्रश्न
Multiply:
4x + 2y by 3xy
Multiply:
1 + 4x by x
Multiply:
− x + y − z and − 2x
Multiply:
xy − yz and x2yz2
Multiply:
3a + 4b − 5c and 3a
Multiply:
x – 5 and x + 3
Multiply:
(x + 9y) and (x – 5y)
Find the product of xy − ab and xy + ab
Simplify:
− 64x4y3z ÷ 4x3y2z
Divide:
`(2"a"^2)/(9"b"^2)` by `(3"b")/(2"a")`
