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प्रश्न
Divide. Write the quotient and the remainder.
40a3 ÷ (−10a)
उत्तर
40a3 ÷ (−10a)
\[= \frac{40 a^3}{\left( - 10a \right)}\]
\[ = \frac{\left( - 4 \right) \times \left( - 10a \right) \times a^2}{\left( - 10a \right)}\]
\[ = - 4 a^2\]
So, quotient = \[- 4 a^2\] and remainder = 0
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