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प्रश्न
Domain of the function f(x) = `sqrt(1 + 4x - x^2)` is ______
पर्याय
`-sqrt5 ≤ x ≤ sqrt5`
2 - `sqrt5 ≤ x ≤ 2 + sqrt5`
-2 ≤ x ≤ 2
-2 `+ sqrt5 ≤ x ≤ -2 - sqrt5`
MCQ
रिकाम्या जागा भरा
उत्तर
Domain of the function f(x) = `sqrt(1 + 4x - x^2)` is `underline(2 - sqrt5 ≤ x ≤ 2 + sqrt5)`.
Explanation:
The quantity under root is positive when 1 + 4x - x2 ≥ 0
i.e. 5 - (x - 2)2 ≥ 0
2 - `sqrt5 ≤ x ≤ 2 + sqrt5`
shaalaa.com
Continuity in the Domain of the Function
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