Advertisements
Advertisements
प्रश्न
Draw the graph of the following function:
f(x) = e-2x
उत्तर
For x = 0, f(x) becomes 1 i.e., the curve cuts the y-axis at y = 1.
For no real value of x, f(x) equal to 0. Thus it does not meet the x-axis for real values of x.
APPEARS IN
संबंधित प्रश्न
Determine whether the following function is odd or even?
f(x) = `log (x^2 + sqrt(x^2 + 1))`
Determine whether the following function is odd or even?
f(x) = x2 – |x|
Let f be defined by f(x) = x3 – kx2 + 2x, x ∈ R. Find k, if ‘f’ is an odd function.
If f(x) = ex and g(x) = loge x then find (f + g)(1)
Draw the graph of the following function:
f(x) = 16 – x2
If f(x) = `1/(2x + 1)`, x > `-1/2`, then show that f(f(x)) = `(2x + 1)/(2x + 3)`
If f(x) = `(1 - x)/(1 + x)` then f(-x) is equal to:
Which of the following function is neither even nor odd?
The range of f(x) = |x|, for all x ∈ R is:
The graph of f(x) = ex is identical to that of:
