मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

Draw the graph of y = x2 – 5x – 6 and hence solve x2 – 5x – 14 = 0 - Mathematics

Advertisements
Advertisements

प्रश्न

Draw the graph of y = x2 – 5x – 6 and hence solve x2 – 5x – 14 = 0

आलेख
बेरीज

उत्तर

Let y = x2 – 5x – 6

(i) Draw the graph of y = x2 – 5x – 6 by preparing the table of values as below.

x – 4 – 3 – 2 – 1 0 1 2 3 4 5 6 7 8
x2 16 9 4 1 0 1 4 9 16 25 36 49 64
– 5x 20 15 10 5 0 – 5 – 10 – 15 – 20 – 25 – 30 – 35 – 40
– 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6
y 30 18 8 0 – 6 – 10 – 12 – 12 – 10 – 6 0 8 18

(ii) Plot the points (– 3, 18), (– 2, 8), (– 1, 0), (0, – 6), (1, – 10), (2, – 12), (3, – 12), (4, – 10), (5, – 6), (6, 0) and (7, 8).

(iii) Join the points by a free hand to get smooth curve.

(iv) To solve x2 – 5x – 14 = 0, subtract x2 – 5x – 14 = 0 from y = x2 – 5x – 6.

y = x2 – 5x – 6
0 = x2 – 5x – 14
      (–)   (+)   (+)
y               =  8

The equation y = 8 represent a straight line draw a straight line through y = 8 intersect the curve at two places.

From the two points draw a perpendicular line to the X-axis it will intersect at – 2 and 7.

The solution is – 2 and 7

shaalaa.com
Quadratic Graphs
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.15 [पृष्ठ १३७]

APPEARS IN

सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 3 Algebra
Exercise 3.15 | Q 6 | पृष्ठ १३७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×