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प्रश्न
Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI.
उत्तर
\[\begin{array}{cc}
\phantom{...............................................}\ce{H}\\
\phantom{...............................................}|\\
\ce{\underset{(1-ethoxy-prop-1-ene)}{CH3 - CH = CH} - \underset{\bullet\bullet}{\overset{\bullet\bullet}{O}} - C2H5 ->[H - I][\Delta] CH3 - CH = CH - O - C2H5}
\end{array}\]
\[\ce{\underset{(1-iodo-prop-1-ene)}{CH3 - CH = CH - I} <-[+I^Θ] CH3 - CH = \overset{⊕}{C}H + C2H5OH}\]
This reaction follows SN1 mechanism because in this reaction the more stable carbocation is formed that is double bonded carbocation. Therefore, the given molecule reacts with HI to form ethanol and 1-iodo prop-1-ene.
\[\ce{CH3 - CH = CH - O - C2H5 ->[HI/\Delta] \underset{(1-iodo-prop-1-ene)}{CH3 - CH = CH - I} + \underset{(ethanol)}{C2H5OH}}\]
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संबंधित प्रश्न
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On reacting with neutral ferric chloride, phenol gives ____________.
Arrange the following in the increasing order of their boiling point and give a reason for your ordering.
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Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI
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Acid catalysed hydration
What will be the product (X and A) for the following reaction:
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Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI.
Identify the product(s) is/are formed when 1-methoxy propane is heated with excess HI. Name the mechanism involved in the reaction.
Predict the major product, when 2-methyl but -2-ene is converted into an alcohol in each of the following methods.
Acid catalysed hydration
Predict the major product, when 2-methyl but – 2 – ene is converted into an alcohol in each of the following method.
Acid catalysed hydration.
