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प्रश्न
Draw the M.O diagram for oxygen molecule calculate its bond order and show that O2 is paramagnetic.
उत्तर
MO Diagram for O2 molecule
Electronic configuration of O atom:
1s2 2s2 2p4
Electronic configuration of O2 molecule:
σ1s2, σ1s*2, σ2s2, σ2s*2, σ2px2, π2py2 π2pz2 π2py*1 π2pz*1
Bond order = `("N"_"b" - "N"_"a")/2`
`= (10 - 6)/2`
= 2
The molecule has two unpaired electrons hence it is paramagnetic.
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