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प्रश्न
E and F are the points in sides DC and AB respectively of parallelogram ABCD. If diagonal AC
and segment EF intersect at G; prove that:
बेरीज
उत्तर
In ∆EGC and ∆FGA
∠ECG = ∠FAG (Alternate angles as AB ∥ CD)
∠EGC = ∠FGA (Vertically opposite angles)
∆EGC ~ ∆FGA (By AA – similarity)
`∴("EG")/("FG")=("CG")/("AG")`
AG × EG = FG × CG
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