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प्रश्न
Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative?
पर्याय
CH3 – CH2 – *CH2 –CH3
CH3 – *CH = CH – CH3
CH3 – CH2 – C ≡ *CH
CH3 – CH2 – CH = *CH2
उत्तर
CH3 – CH2 – C ≡ *CH
Explanation:
Electronegativity increases as the state of hybridization changes from sp3 to sp2 and sp2 to sp. Thus, sp hybridized carbon has the highest electronegativity.
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संबंधित प्रश्न
Indicate the σ and π bonds in the following molecules:
CH3NO2
Indicate the σ and π bonds in the following molecule:
HCONHCH3
What is hybridization state of each carbon atom in the following compound?
CH2 = C = O
What is hybridization state of each carbon atom in the following compound?
CH3CH = CH2
Assertion (A): All the carbon atoms in H2C = C = CH2 are sp2 hybridised
Reason (R): In this molecule all the carbon atoms are attached to each other by double bonds.
Which one of the following has sp3, sp2, or sp hybrid orbitals in the ratio 6 : 3 : 2?
Indicate the σ and π bonds in the following molecules:
HCONHCH3
Indicate the σ and π bonds in the following molecule:
\[\ce{HCONHCH3}\]
Indicate the σ and π bonds in the following molecules:
\[\ce{HCONHCH3}\]
Indicate the σ and π bonds in the following molecule:
\[\begin{array}{cc}
\ce{HCONHCH3}
\end{array}\]