Question

E.N. of Si is ______. (Covalent radius of Si = 1.175 Å)

पर्याय

• 0.096

• 1.823

• 0.025

• 5.369

Answer 1

E.N. of Si is 1.823.

Explanation:

(E.N.) Allred Rochow

`= 0.744 + 0.359/"r"^2 " Z"_"eff"`

`"Z"_"eff" " of" " Si"^+ => "Si" = 1"s"^2  2"s"^2  2"p"^6  3"s"^2  3"p"^2`

`therefore "Z"_"eff" = 14 - (3 xx 0.35 + 8 xx 0.85 + 2 xx 1)`

= 4.15

∴ E.N. = `0.744 + 0.359/((1.175)) xx 4.15`

∴ E.N. = 1.823