Question

Equilibrium constant for a reaction is 20. What is the value of ΔG° at 300 K? (R = 8 x 10^-3 kJ)

पर्याय

• 16.63 kJ mol^-1

• - 5.527 kJ mol^-1

• - 2.763 kJ mol^-1

• None of the above

Answer 1

None of the above

Explanation:

Given,

K_eq = 20

Temperature (T) = 300K

R = 8 × 10^-3 kJ

We have, ΔG° = - 2.303 × R × T × log K_eq

= - 2.303 × 8 × 10^-3 × log 20 × 300 (log 20 = 1.301)

= 7.191 kJ mol^-1