Advertisements
Advertisements
प्रश्न
Evaluate:
`(tan^2 60^@)/(sin^2 60^@ + cos^2 30^@)`
मूल्यांकन
उत्तर
Given:
`(tan^2 60^@)/(sin^2 60^@ + cos^2 30^@)`
`tan 60^@ = sqrt3, "so" tan^2 60^@ = (sqrt3)^2 = 3`.
`sin 60^@ = (sqrt3)/2, "so" sin^2 60^@ = ((sqrt3)/(2))^2 = 3/4`.
`cos 30^@ = (sqrt3)/(2), "so" cos^2 30^@ = ((sqrt3)/(2))^2 = 3/4`.
`sin^2 60^@ + cos^2 30^@ = 3/4 + 3/4 = 6/4 = 3/2`
`3/(3/2)`
= `3 xx 2/3`
= 2
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
