Question

Evaluate the following C++ expressions where x, y, z are integers and m, n are floating-point numbers. The value of x = 5, y = 4 and m=2.5;

z = m * x + y;

Answer 1

z = m * x + y;
= 2.5 * 5 + 4 (m is float type, so x value is promoted to float [implicit conversion])
= 12.5 + 4 ‘
= 16 (2 is int type. So ‘.2’, the fractional part is discarded)