Advertisements
Advertisements
प्रश्न
Evaluate: xz (x2 + y2) for x = 2, y = 1 and z= 1.
बेरीज
उत्तर
For x = 2, y = 1 and z = 1
xz (x2 + y2)
2(1) × (22 + 12)
2 × (4 + 1)
2 × 5
= 10
shaalaa.com
Multiplying a Polynomial by a Polynomial
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Simplify: (5a + 5b – c) (2b – 3c)
Simplify : (3y + 4z) (3y – 4z) + (2y + 7z) (y + z)
Evaluate (x5) × (3x2) × (-2x) for x = 1.
If x = 2 and y = 1; find the value of (−4x2y3) × (−5x2y5).
Evaluate: (3x – 2)(x + 5) for x = 2.
Evaluate: (2x – 5y)(2x + 3y) for x = 2 and y = 3.
Evaluate: xy2(x – 5y) + 1 for x = 2 and y = 1.
Evaluate: 2x(3x – 5) – 5(x – 2) – 18 for x = 2.
Multiply and then verify :
−3x2y2 and (x – 2y) for x = 1 and y = 2.
Multiply: 2x2 – 4x + 5 by x2 + 3x – 7