Advertisements
Advertisements
प्रश्न
Exercise Problems.
An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 m and 20 s?
उत्तर
Given: Diameter of circular track = 200m
time to complete = 40s
Formula: Circumference of circular track = d. π m
speed = `"distance"/"time"`
Solution:
Circumference of the track = d.π
= 200 × 3.14 = 628m
speed = `"628m"/"40s"` = 15.7 ms– 1
Distance covered in 2 min 20 s = speed × time
In the given time athlete covers 31/2 rounds = 2198m
The final position of athlete is as shown in figure (A – initial position, B – final position)
∴ Displacement = Distance × time
= 200 m
APPEARS IN
संबंधित प्रश्न
An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s?
A body is moving along a circular path of radius R. What will be the distance travelled and displacement of the body when it completes half a revolution ?
When is the magnitude of displacement equal to the distance?
What can you say about the nature of motion of a body if its displacement-time graph is A straight line inclined to the time axis with an acute angle?
Figure shows the displacement-time graph of two vehicles A and B moving along a straight road. Which vehicle is moving faster? Give reason.
Explain the following concept in your own words with everyday examples:
Distance
A car covers 90 km in `1 1/2` hours towards east. Calculate
- displacement of car,
- its velocity in (a) kmh−1 (b) ms−1.
How can you find the following?
Velocity from a displacement – time graph.
A body is moving along a circular path of radius r. What will be the distance and displacement of the body when it completes:
Half a revolution
In which of the following cases of motions, the distance moved and the magnitude of displacement are equal?
