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प्रश्न
Expand.
(13 + x) (13 − x)
बेरीज
उत्तर
(13 + x) (13 − x)
= `(13)^2+ ("x" – "x") 13 + "x" xx (-"x")` …[∵ (x + a) (x + b) = x2 + (a + b)x + ab]
= `169 + 0 × 13 – "x"^2`
= `169 – "x"^2`
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