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प्रश्न
Expand the following square, using suitable identities
(b – 7)2
बेरीज
उत्तर
(b – 7)2
Comparing (b – 7)2 with (a – b)2 we have a = b and b = 7
(a – b)2 = a2 – 2ab + b2
(b – 7)2 = b2 – 2(b)(7) + 72
(b – 7)2 = b2 – 14b + 49
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पाठ 3: Algebra - Exercise 3.1 [पृष्ठ ६२]
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