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प्रश्न
Expand.
`(x + 1/x)(x - 1/x)`
बेरीज
उत्तर
`(x+1/x)(x-1/x)`
= `(x)^2 + {1/x + (-1/x)}x + (1/x) xx (-1/x)`
= `x^2 + (1/x - 1/x)x - 1/x^2`
= `x^2 - 1/x^2`
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