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प्रश्न
Expand: `("y" - 3/"y")^2`
बेरीज
उत्तर
`("y" - 3/"y")^2`
Using the identity (a - b)2 = a2 - 2ab + b2
= `"y"^2 - 2 xx "y" xx 3/"y" + (3/"y")^2`
`= "y"^2 - 6 + 9/"y"^2`
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