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प्रश्न
Explain the conditions for equilibrium of forces in space.
उत्तर
A body is said to be in equilibrium if the resultant force and the resultant momentum acting on a body is zero.
For a body in space to remain in equilibrium, following conditions must be satisfied:
(1) Algebraic sum of the X components of all the forces is zero.
ΣFx =0
(2)Algebraic sum of the Y components of all the forces is zero. ΣFy=0
(3)Algebraic sum of the Z components of all the forces is zero. ΣFz=0
(4)Algebraic sum of the moment of all the forces about any point in the space is zero.
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संबंधित प्रश्न
Determine the force P required to move the block A of 5000 N weight up the inclined plane, coefficient of friction between all contact surfaces is 0.25. Neglect the weight of the wedge and the wedge angle is 15 degrees.
Given : Weight of block A = 5000 N
μs=0.25
Wedge angle = 15º
To find : Force P required to move block A up the inclined plane
Refer to figure.If the co-efficient of friction is 0.60 for all contact surfaces and θ = 30o,what force P applied to the block B acting down and parallel to the incline will start motion and what will be the tension in the cord parallel to inclined plane attached to A.
Take WA=120 N and WB=200 N.
Two blocks A and B are resting against the wall and floor as shown in the figure.Find the minimum value of P that will hold the system in equilibrium. Take μ=0.25 at the floor,μ=0.3 at the wall and μ=0.2 between the blocks.
Given : μ=0.25 at floor
μ=0.2 between blocks
To find : Minimum value of force P
