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प्रश्न
\[\ce{F2}\] acts as a strong oxidising agent due to ______.
पर्याय
low `Delta_"bond"`H° and low `Delta_"hyd"`H°
low `Delta_"bond"`H° and high `Delta_"hyd"`H°
high `Delta_"bond"`H° and high `Delta_"eg"`H°
low `Delta_"hyd"`H° and low `Delta_"eg"`H°
MCQ
रिकाम्या जागा भरा
उत्तर
low `Delta_"bond"`H° and high `Delta_"hyd"`H°
Explanation:
\[\ce{F2}\] acts as a strong oxidising agent because its \[\ce{F - F}\] bond dissociation enthalpy `Delta_"bond"`H° is very low due to strong repulsions between the lone pairs on fluorine atoms. Additionally, the fluoride ion \[\ce{F-}\] has a very high hydration enthalpy `Delta_"hyd"`H°, which stabilises it, making oxidation by \[\ce{F2}\] highly favourable.
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