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प्रश्न
Factorise completely:
5ap2 + 11ap + 2a
बेरीज
उत्तर
5ap2 + 11ap + 2a
= a [5p2 + 11p + 2]
= a [5p2 + 10p + p + 2]
= a [5p(p + 2) + 1(p + 2)]
= a [(p + 2) (5p + 1)]
= a (p + 2) (5p + 1)
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Factorising Completely
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