Advertisements
Advertisements
प्रश्न
Factorise the following by grouping the terms:
2a + b + 3c - d + (2a + b)3 + (2a + b)2(3c - d)
बेरीज
उत्तर
2a + b + 3c - d + (2a + b)3 + (2a + b)2(3c - d)
= (2a + b + 3c - d) + [(2a + b)3 + (2a + b)2(3c - d)]
= 1(2a + b + 3c - d) + (2a + b)2(2a + b + 3c - d)
= (2a + b + 3c - d)[1 + (2a + b)2].
shaalaa.com
Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : a4 - 2a3 - 4a + 8
Factorise using the grouping method :
a2 + 4b2 - 3a + 6b - 4ab
Factorise : 6a2 - 3a2b - bc2 + 2c2
Factorise : 3a2b - 12a2 - 9b + 36
factorise: 2x2 + xy - 6y2
factorise: 14x2 + x - 3
factorise: 1 − (2x + 3y) − 6(2x + 3y)2
factorise: 1 - 3x - 3y - 4(x + y)2
Factorise the following by grouping the terms:
9 + 3xy + x2y + 3x
Factorise the following by grouping the terms:
x2 - (p + q)x + pq
