Advertisements
Advertisements
प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y3 – 2aby2 + b2y
बेरीज
उत्तर
We have,
a2y3 – 2aby2 + b2y = y(a2y2 – 2aby + b2)
= y[(ay)2 – 2 · ay · b + b2]
= y(ay – b)2
= y(ay – b)(ay – b)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
APPEARS IN
संबंधित प्रश्न
Expand `("x"-2/"x")^2`
(a – 1)2 = a2 – 1
Factorise the following using suitable identity
64x2 – 112xy + 49y2
Simplify: (a + b)2 – (a – b)2
A square lawn has a 2 m wide path surrounding it. If the area of the path is 136 m2, find the area of lawn
Square of 9x – 7xy is ______.
(a – b) ______ = a2 – 2ab + b2
1032 – 1022 = ______ × (103 – 102) = ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 8x + 16
Factorise the following.
p2 – 13p – 30
