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प्रश्न
factorise: x2 + 6x + 9 - 4y2
बेरीज
उत्तर
x2 + 6x + 9 - 4y2
= (x)2 + 2 × x × 3 + (3)2 - (2y)2
...[(a + b)2 = a2 + 2ab + b2]
...[a2 - b2 = (a + b)(a - b)]
= (x + 3)2 - (2y)2
= (x + 3 + 2y) (x + 3 - 2y)
= (x + 2y + 3) (x - 2y + 3)
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Factorisation by Difference of Two Squares
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