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प्रश्न
Factorise.
`y^3 + 1/(8y^3)`
बेरीज
उत्तर
It is known that,
a3 + b3 = (a + b)(a2 – ab + b2)
`y^3 + 1/(8y^3)`
Here, a = y and b = `1/2y`
`y^3 + 1/(8y^3) = (y + 1/(2y))[y^2 - y(1/(2y)) + (1/(2y))^2]`
`(y + 1/(2y))(y^2 1/2 + 1/(4y^2))`
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