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प्रश्न
Fig. 13.4 shows an oscillating pendulum.
Time taken by the bob to move from A to C is t1 and from C to O is t2. The time period of this simple pendulum is
पर्याय
(t1 + t2)
2(t1 + t 2)
3(t1 + t 2)
4(t1 + t 2)
उत्तर
4(t1 + t 2)
Explanation:
Time taken by the bob to move from
A to O = t1 + t2
= tAO = tOA
Similarly, tOB = t1 + t2 = tBO
So, time period = tAO + tOB + tBO + tOA
= 4(t1 + t2)
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