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प्रश्न
Fill in the boxe to show the corresponding energy transformation.
उत्तर
Electrical energy ⇌ Sound energy
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संबंधित प्रश्न
In which of the following cases, is work being done?
(i) A man pushing a wall.
(ii) a coolie standing with a load of 12 kgf on his head.
(iii) A boy climbing up a staircase.
A vessel containing 50 kg of water is placed at a height 15 m above the ground. Assuming the gravitational potential energy at ground to be zero, what will be the gravitational potential energy of water in the vessel? (g = 10 m s-2)
If the work done by a force in moving an object through a distance of 20 cm is 24.2 J, what is the magnitude of the force?
A max X goes to the top of a building by a vertical spiral staircase. Another man Y of the same mass goes to the top of the same building by a slanting ladder. Which of the two does more work against gravity and why?
A girl weighing 400 N climbs a vertical ladder. If the value of g be 10 m s−2, the work by her after climbing 2 m will be :
How many watts equal one horse power?
What is the work done when the object acted upon by a force remains at rest?
Name the physical quantity associated with the 'rate of doing work'.
Calculate the amount of work done by a child carrying a bag of 20 kg when he moves a distance of 40 m in
(a) Vertical direction, and
(b) Horizontal direction
Define energy and state the unit of energy and the law of conservation of energy.
Fill in the boxe to show the corresponding energy transformation.
State the energy changes which take place when An electric bulb glows when it is connected to a source of electric current.
How much energy is gained by a box of mass 20 kg when a man, runs carrying the box with a speed of 3 m/s-1 to catch the bus?
A coolie, with a load of 30 kg on his head, walks on the platform. If he walks a distance of 60 m, what is the work done by him?
Can two agents, doing the same work, have different power?
A is a push or a pull ______.
Force acting on a particle moving in a straight line varies with the velocity of the particle v as F = `K/v`, where K is a constant. The work done by this force in time t is
