Advertisements
Advertisements
प्रश्न
Find Is 68 a term of the A.P. 7, 10, 13, ...?
उत्तर
In the given problem, we are given an A.P and the value of one of its term.
We need to find whether it is a term of the A.P or not.
So here we will use the formula, `a_n = a + (n - 1)d`
Here, A.P is 7, 10, 13
`a_n = 68`
a = 7
Now
Common difference (d) = `a_1 - a`
= 10 - 7
= 3
Thus using the above mentioned formula we get
`68 = 7 + (n - 1)3`
68 - 7 = 3n - 3
61 +3 = 3n
`n = 64/3`
Since the value of n is a fraction
Thus 68 is not the term of the given A.P
Therefore the answer is NO
APPEARS IN
संबंधित प्रश्न
For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P?
The first three terms of an AP respectively are 3y – 1, 3y + 5 and 5y + 1. Then y equals:
(A) –3
(B) 4
(C) 5
(D) 2
For an A.P., find S7 if a = 5 and d = 4.
Which of the following sequences are arithmetic progressions? For those which are arithmetic progressions, find out the common difference.
1.0, 1.7, 2.4, 3.1, ...
Find the 10th term of the A.P. −40, −15, 10, 35, ...
Write the expression an- ak for the A.P. a, a + d, a + 2d, ... Hence, find the common difference of the A.P. for which a10 −a5 = 200
One person borrows ₹ 4,000 and agrees to repay with a total interest of ₹ 500 in 10 instalments. Each instalment being less than the preceding instalment by ₹ 10. What should be the first and the last instalments?
If p, q, r and s are in A.P. then r - q is ______.
If p, q, r are in AP, then p3 + r3 - 8q3 is equal to ______.
Verify that the following is an AP, and then write its next three terms.
`sqrt(3), 2sqrt(3), 3sqrt(3),...`