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Find a polynomial equation of minimum degree with rational coefficients, having 5-3 as a root - Mathematics

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प्रश्न

Find a polynomial equation of minimum degree with rational coefficients, having `sqrt(5) - sqrt(3)` as a root

बेरीज

उत्तर

The given one roots of the polynomial equation are `(sqrt(5) - sqrt(3))`

The other roots are `(sqrt(5) + sqrt(3), (- sqrt(5) + sqrt(3))` and `(- sqrt(5) - sqrt(3))`.

The quadratic factor with roots `(sqrt(5) - sqrt(3))` and `(sqrt(5) + sqrt(3))` is

= x2 – x(S.O.R) + P.O.R

= `x^2 - x(2sqrt(5)) + (sqrt(5) - sqrt(3))(sqrt(5) + sqrt(3))`

= `x^2 - 2sqrt(5)x + 2`

The other quadratic factors with roots `(- sqrt(5) + sqrt(3))(- sqrt(5) - sqrt(3))` is

= x2 – x (S.O.R) + P.O.R

= `x^2 - x(- 2sqrt(5)) + (5 - 3)`

= `x^2 + 2sqrt(5)x + 2`

To rationalize the co-efficients with minimum degree

`(x^2 - 2sqrt(5)x + 2)(x^2 + 2sqrt(5)x + 2)` = 0

⇒ `(x^2 + 2)^2 - (2sqrt(5)x)^2` = 0

⇒ x4 + 4 + 4x2 – 20x2 = 0

⇒ x4 – 16x2 + 4 = 0 

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Nature of Roots and Nature of Coefficients of Polynomial Equations
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Theory of Equations - Exercise 3.2 [पृष्ठ ११२]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 3 Theory of Equations
Exercise 3.2 | Q 4 | पृष्ठ ११२
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