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प्रश्न
Find the general solution of the equation `4cos^2x=1`
उत्तर
Given:
`4cos^2x=1`
`cos^2x=1/4`
`cos^2x=cos^2(pi/3)`
`["Using " cos^2x=cos^2alpha => x=npi+-alpha]`
`x=npi+-pi/3" where " n in Z`
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