Advertisements
Advertisements
प्रश्न
Find the greatest number of 6 digits exactly divisible by 24, 15 and 36.
उत्तर
TO FIND: Greatest number of 6 digits exactly divisible by 24, 15 and 36
The greatest 6 digit number be 999999
24, 15 and 36
`24=2^2xx3`
`15=3xx5`
`36=2^2xx3^2`
L.C.M of 24,15 and 36 = 360
Since `99999/360 =2777xx360+279`
Therefore, the remainder is 279.
Hence the desired number is equal to
`=999999-279`
= 999720
Hence 999720 is the greatest number of 6 digits exactly divisible by 24, 15 and 36.
APPEARS IN
संबंधित प्रश्न
Prove that the product of three consecutive positive integer is divisible by 6.
For any positive integer n , prove that n3 − n divisible by 6.
Show that every positive even integer is of the form 4m and that every positive odd integer is of the form 4m + 1 for some integer m.
In a seminar, the number of participants in Hindi, English and mathematics are 60, 84 and 108 respectively. Find the minimum number of rooms required, if in each room, the same number of participants are to be seated and all of them being in the same subject .
Express each of the following as a rational number in its simplest form:
(i) `2. bar(4)`
The product of two numbers is 1050 and their HCF is 25. Find their LCM.
Show that the following numbers are irrational.
Every even integer is of the form 2m, where m is an integer (True/False).
The remainder when the square of any prime number greater than 3 is divided by 6, is
If d is the Highest Common Factor of 32 and 60, find x and y satisfying d = 32x + 60y