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प्रश्न
Find mean proportional of `( x + y)/( x - y), (x^2 - y^2)/(x^2y^2)`
उत्तर
If b is the mean proportional of a and c, then `b^2 = ac`
Mean proportional of `[ x + y]/[ x - y] and [ x^2 - y^2]/[ x^2y^2]`
`therefore b^2 = [x + y]/[x - y] xx [ x^2 - y^2]/[x^2y^2]`
`b^2 = [x + y]/[x -y] xx [( x - y)( x + y)]/( x^2y^2)`
`therefore b^2 = [(x + y)^2]/(xy)^2`
`therefore b = [x + y]/(xy)`
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