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प्रश्न
Find the resultant of the force system as shown in the given figure.
उत्तर
Taking forces having direction upwards as positive. Net force = 200+300-200-300
=0 N
Taking moments of the forces about the point A Taking anticlockwise moment direction as positive
∴ MA = 200 x7 +300 x 5 – 300 x2
=2300 Nm (anticlockwise direction)
The resultant force is 0.
Net moment is 2300 Nm(anticlockwise)
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संबंधित प्रश्न
In the rocket arm shown in the figure the moment of ‘F’ about ‘O’ balances that P=250 N.Find F. 
Find the force F4 , so as to give the resultant of the force as shown in the figure given below.
Given : Forces and their resultant
To find : Force F4
The resultant of the three concurrent space forces at A is 𝑹̅ = (-788𝒋̅) N. Find the magnitude of F1,F2 and F3 forces.
Given : A=(0,12,0)
B=(-9,0,0)
C=(0,0,5)
D=(3,0,-4)
Resultant of forces = (-788𝑗̅) N
To find : Magnitude of forces F1,F2,F3
