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प्रश्न
Find the 12th term from the end of the AP: –2, –4, –6,..., –100.
उत्तर
Given AP: –2, –4, –6,..., –100
Here, first term (a) = –2,
Common difference (d) = –4 – (–2) = –2
And the last term (l) = –100
We know that, the nth term of an AP from the end is an = l – (n – 1)d,
Where l is the last term and d is the common difference.
∴ 12th term from the end,
a12 = –100 – (12 – 1)(–2)
= –100 + (11)(2)
= –100 + 22
= –78
Hence, the 12th term from the end is –78.
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