Question

Find the coordinates of the point of intersection of the pair of lines 6x² + 5xy – 4y² + 7x + 13y – 3 = 0.

Answer 1

Here a, = 6, b = – 4, c = – 3

f = `13/2,` g = `7/2`, h = `5/2`

Point of intersection = `((hf - bg)/(ab - h^2), (gh - af)/(ab - h^2))`

= `((5/2*13/2 - (-4) 7/2)/(-24 - 25/4), (7/2*5/2 - 6*13/2)/(-24 - 25/4))`

= (–1, 1)