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प्रश्न
Find the greatest number which divides 2011 and 2623, leaving remainders 9 and 5 respectively.
उत्तर
Clearly, we have to find the number which exactly divides (2011 − 9) and (2623 − 5).
So, the required number is the HCF of 2002 and 2618.
∴ The required number is 154.
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संबंधित प्रश्न
Test the divisibility of the following numbers by 5:
4965
Test the divisibility of the following numbers by 5:
23590
Test the divisibility of the following numbers by 7:
14126
Test the divisibility of the following number by 11:
901351
In the following number, replace * by the smallest number to make it divisible by 3:
27*4
In the following number, replace * by the smallest number to make it divisible by 3:
6*1054
In the following number, replace * by the smallest number to make it divisible by 9:
835*86
Test the divisibility of 19083625 by 11.
Which of the following numbers is divisible by 4?
Using divisibility tests, determine which of the following numbers are divisible by 2; by 3; by 4; by 5; by 6; by 8; by 9; by 10; by 11 (say, yes or no):
|
Number |
Divisible by |
||||||||
|
2 |
3 |
4 |
5 |
6 |
8 |
9 |
10 |
11 |
|
|
128 |
Yes |
No |
Yes |
No |
No |
Yes |
No |
No |
No |
|
990 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
|
1586 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
|
275 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
|
6686 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
|
639210 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
|
429714 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
|
2856 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
|
3060 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
|
406839 |
______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ | ______ |
