Advertisements
Advertisements
प्रश्न
Find the HCF set of numbers using prime factorisation method.
45, 55, 95
उत्तर
45, 55, 95
Prime factorisation of 45 = 3 × 3 × 5
Prime factorisation of 55 = 5 × 11
Prime factorisation of 95 = 5 × 19
Common factors of 45, 55, 95 = 5
HCF (45, 55, 95) = 5
| 3 | 45 |
| 3 | 15 |
| 5 | 5 |
| 1 |
| 5 | 55 |
| 11 | 11 |
| 1 |
| 5 | 95 |
| 19 | 19 |
| 1 |
APPEARS IN
संबंधित प्रश्न
Two ropes, one 8 meters long and the other 12 meters long are to be cut into pieces of the same length. What will the maximum possible length of each piece be?
The number of students of Std 6th and Std 7th who went to visit the Tadoba Tiger Project at Chandrapur was 140 and 196 respectively. The students of each class are to be divided into groups of the same number of students. Each group can have a paid guide. What is the maximum number of students there can be in each group ? Why do you think each group should have the maximum possible number of students?
Find the HCF:
56, 32
Find the prime factor of the following numbers and find their LCM and HCF.
153, 187
Simplify:
`322/391`
Find the HCF of the numbers in each of the following, using the prime factorization method:
272, 425
For the below pair of numbers, verify that their product = (HCF × LCM).
490, 1155
Find the length of the longest rope that can be used to measure exactly the ropes of length 1 m 20 cm, 3 m 60 cm and 4 m
Find the HCF of the following numbers:
36, 84
Three boys step off together from the same spot. Their steps measure 63 cm, 70 cm, and 77 cm respectively. What is the minimum distance each should cover so that all can cover the distance in complete steps?
