Advertisements
Advertisements
प्रश्न
Find the largest value of x for which 2(x – 1) ≤ 9 – x and x ∈ W.
उत्तर
2(x – 1) ≤ 9 – x
2x – 2 ≤ 9 – x
2x + x ≤ 9 + 2
3x ≤ 11
`x ≤ 11/3`
x ≤ 3.66
Since, x ∈ W, thus the required largest value of x is 3.
APPEARS IN
संबंधित प्रश्न
`2x <= -7 => (2x)/(-4) >= (-7)/(-4)`
If the replacement set is the set of whole numbers, solve:
`7 - 3x >= - 1/2`
Given x ∈ {integers}, find the solution set of:
–5 ≤ 2x – 3 < x + 2
Find the range of values of x which satisfies
`-2 2/3 <= x + 1/3 < 3 1/3, x in R`
Graph these values of x on the number line.
Solve for x in the following in-equation, if the replacement set is R;
2x - 3 < 7
Solve for x in the following in-equation, if the replacement set is R;
14 - 3x > 5
Solve for x in the following in-equation, if the replacement set is R;
9 - 4x ≤ 15 - 7x
If x + 17 ≤ 4x + 9, find the smallest value of x, when:
x ∈ Z
Solve the following inequalities in the given universal set:
2x - 5 ≤ 5x + 4 < 11, where x ∈ I.
Find the solution set of the following inequalities and draw the graph of their solutions sets:
| x - 1 | > 3
