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प्रश्न
Find the least number which when divided by 16, 36, and 40 leaves 5 as the remainder in each case.
उत्तर
LCM of 16, 36, 40
2 | 16, 36, 40 |
2 | 8, 18, 20 |
2 | 4, 9, 10 |
2 | 2, 9, 5 |
2 | 1, 9, 5 |
3 | 1, 3, 5 |
3 | 1, 1, 5 |
5 | 1, 1, 1 |
LCM = 25 × 32 × 5 = 16 × 9 × 5 = 720
⇒ LCM is 720
Now, Required Number = 720 + 5 = 725
∴ 725 is the least number which when divided by 16, 36, and 40 leaves 5 as the remainder in each case.
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