Advertisements
Advertisements
प्रश्न
Find the quadratic equation, whose solution set is :
(-2,3}
उत्तर
Since solution set is {-2,3)
⇒ x = -2 or x = 3
⇒ x + 2 = 0 or x - 3 = 0
⇒(x + 2)(x -3) = 0
⇒ x2 - 3x + 2x - 6 = 0
⇒ x2 - x - 6 = 0 which is the required equation.
APPEARS IN
संबंधित प्रश्न
Solve `x + 1/x = 2.5`
Find the quadratic equation, whose solution set is: {-2, 3}
Solve the following equation for x and give, in the following case, your answer correct to one decimal place:
5x2 + 10x – 3 = 0
Solve the following equation for x and give, in the following case, your answer correct to 2 decimal places:
x2 – 5x – 10 = 0
`48x^2-13x1=0`
`2x^2-x+1/8=0`
`x^2-(2b-1)x+(b^2-b-20)=0`
Solve the following equation by using formula :
4x2 – 4ax + (a2 – b2) = 0
Solve the following equation by using formula:
`x - (1)/x = 3, x ≠ 0`
The coefficient of x2 in x2 + 2x + 9 = `3x(x/2 - 1)` is ______.